-0.01x^2-x-16=0

Solution for -0.01x^2-x-16=0 equation:

-0.01x^2-x-16=0

We add all the numbers together, and all the variables

-0.01x^2-1x-16=0

a = -0.01; b = -1; c = -16;
Δ = b2-4ac
Δ = -12-4·(-0.01)·(-16)
Δ = 0.36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-1)-\sqrt{0.36}}{2*-0.01}=\frac{1-\sqrt{0.36}}{-0.02}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-1)+\sqrt{0.36}}{2*-0.01}=\frac{1+\sqrt{0.36}}{-0.02}
$